Sometimes you may need to find out the fill rate of each column to know the accuracy of given data. One of the things to know is how many columns do not have any values at all.
Let us create the following data set
use tempdb GO create table test ( customer_id int, customer_name varchar(100), dob date, address1 varchar(100), address2 varchar(100) ) insert into test(customer_id,customer_name, dob) select 10001,'Madhivanan','1990-01-01' union all select 10002,'Murugan','1991-10-19' union all select 10003,'Kandhan','1984-04-22'
Now see the result set
select * from test;
As you see, all the values of the columns address1 and address2 are NULL.
You can execute the following dynamic SQL to get the column names for which all values are NULL
declare @sql varchar(8000), @create varchar(1000),@insert varchar(100) select @sql='', @create='Create table #test (col_value sql_variant, col_name varchar(100)) ', @insert=' insert into #test(col_value,col_name) ' select @sql=@sql+' '+@insert+ ' select min('+column_name+') as '+column_name+ ','''+column_name+ ''' from '+table_name from information_schema.COLUMNS where TABLE_NAME='test' and table_catalog='tempdb' set @sql=@create+' '+ @sql+ ' select * from #test where col_value is null' exec(@sql)
After execution, the result is
It listed out two columns address1 and address1 which have all values as NULL. This code can be modified to handle empty calues or any other values easily