What is the result of the following query?

select 78.-100_100

Choose the correct answer

(1) 78 (2) Incorrect syntax near .-100_100 (3) -22 (4) invalid column 78.-100_100

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Month: May 2017

## Question of the month May 2017 – Find out the result of select 78.-100_100

## How to import multiple result sets from Stored procedure?

## Find Nth Maximum value

## ODBC scalar functions – DATE , TIME and Interval functions

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What is the result of the following query?

select 78.-100_100

Choose the correct answer

(1) 78 (2) Incorrect syntax near .-100_100 (3) -22 (4) invalid column 78.-100_100

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One of my friends asked me if it is possible to load multiple resultsets returned from a stored procedure into a temporary table for some analysis purpose. The answer is “It depends”. If all the result sets return same number of columns then it is possible otherwise it is not possible.

Create the following stored procedure

USE tempdb GO CREATE PROCEDURE proc_test AS SELECT 1003 AS number SELECT 28 AS number SELECT 987345 AS number

When you execute this procedure

EXEC proc_test

You get three different result sets

number ----------- 1003 number ----------- 28 number ----------- 987345

Now create a temporary table

CREATE TABLE #temp ( number INT )

Add data to this table by executing the stored procedure

INSERT INTO #temp ( number ) EXEC proc_test

Now check the result from this temporary table

SELECT number FROM #temp

The result is

number --------- 1003 28 987345

So if the table structure is similar to the result set of the stored procedure, it does not matter how many similar result sets are returned, it can be imported to the table. However Currently it is not possible to identify a specific result set from the stored procedure.

“Find Nth Maximum value” is one of the very popular interview questions.

There are several methods to find out the answer. Here are some methods

Consider the following data set

use tempdb create table numbers (number integer) Insert into numbers values(1288) Insert into numbers values(8653) Insert into numbers values(1) Insert into numbers values(390) Insert into numbers values(4009) Insert into numbers values(345) Insert into numbers values(2777)

Assume that you want to find out 3rd maximum value, use one of the following methods

**(1) Use Inner Join**

select t1.number from numbers t1 inner join numbers t2 on t1.number<=t2.number group by t1.number having count(t1.number)=3

**(2) Use Top Operator**

Select top 1 number from ( Select top 3 number from numbers order by number desc ) T order by number asc

**(3) Generate Serial No based on descending order of the values**

select number from ( Select ( select count(*) from numbers where number>=T.number)as Sno , number from numbers as T ) as temp where Sno=3

**(4) Generate Serial No based on descending order of the values in where Clause**

select number from numbers as n where ( select count(*) from numbers where number>=n.number )=3

**(5) Use Aggregate Function**

Select min(number) from ( select top 3 number from numbers order by number desc ) T

**(6) Use Row_number() function**

select number from ( select number, row_number() over (order by number desc) as sno from numbers ) as t where sno=3

Now you can replace 3 to the numbers that you want to find the maximum value

You know very well how to return current date and time using getdate() function. Did you know that there exists ODBC function to return the same?

Select getdate()

returns current date and time

The scalar function

select {fn now()}

also returns current date and time

You can use get month, hour, day, etc using EXTRACT interval function

select {fn extract(month from getdate())}

returns the current month

select {fn extract(day from getdate())}

returns current day value

Here are some functions to explore. These are self-explanatory

select {fn current_date()} select {fn current_time()} select {fn now()} select {fn extract(hour from getdate())} select {fn extract(minute from getdate())} select {fn extract(second from getdate())} select {fn extract(day from getdate())} select {fn extract(month from getdate())} select {fn extract(year from getdate())} select {fn dayname(GetDate())} select {fn monthname(GetDate())} select {fn month(GetDate())} select {fn year(GetDate())}